Matematika (+50) KuMat Kuis Matematika Didefinisikan [tex]\displaystyle f(z)=\int_{\!\!\!\begin{array}{c}0\end{array}}^{\!\!\!\begin{array}{c}z\end{array}}\!\!\!\!g(y)\,dy[/tex] dan [tex]h(x) = x^4[/tex] . [tex](f\circ h)(2) = {\dots} ?[/tex] (Catatan: Jawaban dalam bentuk integral tentu.)

martineluettgenulv – June 08, 2023

(+50) KuMat
Kuis Matematika

Didefinisikan [tex]\displaystyle f(z)=\int_{\!\!\!\begin{array}{c}0\end{array}}^{\!\!\!\begin{array}{c}z\end{array}}\!\!\!\!g(y)\,dy[/tex] dan [tex]h(x) = x^4[/tex] .
[tex](f\circ h)(2) = {\dots} ?[/tex]
(Catatan: Jawaban dalam bentuk integral tentu.)

Jawab:

[tex]\displaystyle \left ( f\circ h \right )(2)=\bf\int_{0}^{16}g(y)\,dy[/tex]

Penjelasan dengan langkah-langkah:

[tex]\displaystyle f(z)=\int_{0}^{z}g(y)\,dy\,,\quad h(x)=x^4[/tex]

[tex]\displaystyle \left ( f\circ h \right )(2)=f\left ( h(2) \right )=f\left ( 2^4 \right )=f(16)[/tex]

[tex]\therefore\ \displaystyle \left ( f\circ h \right )(2)=\int_{0}^{16}g(y)\,dy[/tex]

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